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</math>
==Solution==
Attempting a [[Separation of variables|separable]] solution of the form <math>\psi =U r f(\theta)</math> reduces the problem to
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:<math>f(0)=0,\ f'(0)=-1, \ f(\alpha)=0, \ f'(\alpha)=0</math>
The solution is<ref>{{cite book |last=Acheson |first=David J. |title=Elementary Fluid Dynamics |publisher=Oxford University Press |year=1990 |isbn=0-19-859660-X }}</ref>
:<math>f(\theta) = \frac{1}{\alpha^2 - \sin^2\alpha} [\theta \sin \alpha \sin (\alpha-\theta) - \alpha(\alpha-\theta) \sin\theta]</math>
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