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:<math>x^
The algorithm is derived from [[Newton's method]] (also called the Newton-Raphson method) for finding zeros of a function <math>f(x)</math> beginning with an initial guess. Although Newton's method is iterative, meaning it approaches the solution through a series of increasingly-accurate guesses, it converges very quickly. The rate of convergence is quadratic, meaning roughly that the number of bits of accuracy doubles on each iteration (so improving a guess from 1 bit to 64 bits of precision requires only 6 iterations). For this reason, some variant of Newton's method is often used in computers to calculate square roots.▼
(For integer ''n'' there are ''n'' distinct complex solutions to this equation if <math>A > 0</math>, but only one is positive).
There is a very fast-converging '''n-th root algorithm''' for finding <math>\sqrt[n]{A}</math>:
#Make an initial guess <math>x_0</math>
#Set <math>x_{k+1} = \frac{1}{
#Repeat step 2 until the desired precision is reached.
This is a generalization of the well-known [[Square_root#Square_roots_using_Newton_iteration|square-root algorithm]]. By setting ''n'' = 2, the ''iteration rule'' in step 2 becomes the more familiar square root iteration rule:
▲
:<math>x_{k+1} = x_k - \frac{f(x_k)}{f'(x_k)}</math>▼
For large ''n'', the ''n''-th root algorithm is somewhat less efficient since it requires the computation of <math>x_k^n</math> at each step, but can be efficiently implemented with a good exponentiation algorithm.
== Derivation from Newton's Method ==
[[Newton's method]] is a method for finding a zero of a function ''f(x)''. The general iteration scheme is:
#Repeat step 2 until the desired precision is reached.▼
:<math>f(x) = x^n - A</math>
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So the derivative is
:<math>f
and the iteration rule is
:<math>x_{k+1} = x_k - \frac{f(x_k
:<math> = x_k - \frac{x_k^n - A}{n x_k^{n-1}}</math>
:<math> = x_k - \frac{x_k}{n}+\frac{A}{n x_k^{n-1}}</math>
:<math> = \frac{1}{n} \left[{(n-1)x_k +\frac{A}{x_k^{n-1}}}\right]</math>
Leading to the general ''n''-th root algorithm:
▲#Set <math>x_{k+1} = \frac{1}{n} \left[{(n-1)x_k +\frac{A}{x_k^{n-1}}}\right]</math>
▲#Repeat step 2 until the desired precision is reached.
[[Category:Root-finding algorithms, Numerical analysis]]
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