Inverse function theorem: Difference between revisions

Revision as of 03:20, 5 March 2007

Revision as of 17:14, 4 May 2007

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:<math>\frac{d}{dx}\arctan x = {{1} \over {\frac{d}{du}\tan u}} = \cos^2{u} = \cos^2{\arctan x} = \left({{1} \over {\sqrt{1+x^2}}}\right)^2 = {{1} \over {1+x^2}}.</math>

[[Category:MultivariateMultivariable calculus]]

[[Category:Differential topology]]

[[Category:Inverse functions]]

[[Category:Mathematical theorems]]

[[de:Satz über die inverse Funktion]]