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== sharlatans ==
I think, that people who gave formula how calculate Deutsch-Jzosa algorithm, himselfs don't understood what they do. Becouse imposible to calculate somehing concrete with this selfinvent trough dreams formula <math>\frac{1}{2^n}\sum_{x=0}^{2^n-1} (-1)^{f(x)} \sum_{y=0}^{2^n-1}(-1)^{x\cdot y} |y\rangle=
\sum_{y=0}^{2^n-1} [\sum_{x=0}^{2^n-1}(-1)^{f(x)} (-1)^{x\cdot y}] |y\rangle </math>.
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