Multiplication algorithm: Difference between revisions

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m Reverted edits by 46.64.255.189 (talk) to last version by Wcherowi
Examples: Re-edit the example of 3 times 11 for fixing the parsing error!
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The method works because multiplication is [[distributivity|distributive]], so:
:3×11= 3×(1×2<sup>0</sup> + 1×2<sup>1</sup> + 0×2<sup>2</sup> + 1×2<sup>3</sup>)
 
&:: = 3 \times (1 + 2 + 8) \\
: <math>
&:: = 3 + 6 + 24 \\
\begin{align}
&:: = 33.
3 \times 11 & = 3 \times (1\times 2^0 + 1\times 2^1 + 0\times 2^2 + 1\times 2^3) \\
& = 3 \times (1 + 2 + 8) \\
& = 3 + 6 + 24 \\
& = 33.
\end{align}
</math>
 
A more complicated example, using the figures from the earlier examples (23,958,233 and 5,830):