VNP46A3 off-nadir viewing angle
Posted: Sat Nov 16, 2024 5:40 pm America/New_York
Hi, I'm using the VNP46A3 data. My task is to downscale the near-nadir (NN) and off-nadir (ON) products and measure the impact of the viewing angle (VA) on the blooming effect (or PSF) from a geometric perspective. Let me explain.
If I project a viewing cone from nadir the footprint (support) is circular and has minimum area (given fixed viewing height).
If I project the same viewing cone at an angle, off-nadir, then the support is an ellipse and it has a larger area. The greater the angle off-nadir, the more pronounced the ellipse and the larger the area.
The areal increase can be calculated from geometry (my problem).
I am interested to test if the predicted increase in the PSF is equal to this known geometric effect.
What I have done so far is the following:
Assuming that the PSF width (measured in pixels) of the NN product is 1 pixel and the PSF of the ON product is 1.3 pixels. These two values are what I predicted during the downscaling.
To test the predicted value of the ON product, I did:
1/cos(40) ~1.34 which is close to what I predicted. The number 40 is the viewing angle of the sensor (in degrees) and 1 is the PSF width of the NN product.
Here are my questions:
1) is this geometric solution valid? Does it make sense?
2) where can I find the actual degrees of the viewing angle in each NTL image?
Many thanks.
If I project a viewing cone from nadir the footprint (support) is circular and has minimum area (given fixed viewing height).
If I project the same viewing cone at an angle, off-nadir, then the support is an ellipse and it has a larger area. The greater the angle off-nadir, the more pronounced the ellipse and the larger the area.
The areal increase can be calculated from geometry (my problem).
I am interested to test if the predicted increase in the PSF is equal to this known geometric effect.
What I have done so far is the following:
Assuming that the PSF width (measured in pixels) of the NN product is 1 pixel and the PSF of the ON product is 1.3 pixels. These two values are what I predicted during the downscaling.
To test the predicted value of the ON product, I did:
1/cos(40) ~1.34 which is close to what I predicted. The number 40 is the viewing angle of the sensor (in degrees) and 1 is the PSF width of the NN product.
Here are my questions:
1) is this geometric solution valid? Does it make sense?
2) where can I find the actual degrees of the viewing angle in each NTL image?
Many thanks.