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{{Short description|Problem in coordinate geometry}}
{{redirect-distinguish|Distance between two lines|Distance between two skew lines}}
The '''[[distance]] between two [[Parallel (geometry)|parallel]] [[Line (geometry)|
== Formula and proof ==
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:<math>y = mx+b_2\,,</math>
the distance between the two lines is the distance between the two
:<math>y = -x/m \,
This distance can be found by first solving the [[linear systems]]
:<math>\begin{cases}
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\end{cases}</math>
to get the coordinates of the
:<math>\left( x_1,y_1 \right)\ = \left( \frac{-b_1m}{m^2+1},\frac{b_1}{m^2+1} \right)\, ,</math>
Line 54 ⟶ 52:
:<math>d = \frac{|c_2-c_1|}{\sqrt {a^2+b^2}}.</math>
==See also==
*[[Distance from a point to a line]]
==References==
*''Abstand'' In: ''Schülerduden – Mathematik II''. Bibliographisches Institut & F. A. Brockhaus, 2004, {{ISBN|3-411-04275-3}}, pp. 17-19 (German)
*Hardt Krämer, Rolf Höwelmann, Ingo Klemisch: ''Analytische Geometrie und Lineare Akgebra''. Diesterweg, 1988, {{ISBN|3-425-05301-9}}, p. 298 (German)
==External links ==
*Florian Modler: [http://www.emath.de/Referate/Zusammenfassung-wichtiger-Formeln.pdf ''Vektorprodukte, Abstandsaufgaben, Lagebeziehungen, Winkelberechnung – Wann welche Formel?''], pp. 44-59 (German)
*A. J. Hobson: [https://archive.uea.ac.uk/jtm/8/Lec8p5.pdf ''“JUST THE MATHS” - UNIT NUMBER 8.5 - VECTORS 5 (Vector equations of straight lines)''], pp. 8-9
[[Category:Euclidean geometry]]
[[Category:Distance]]
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