Hypergraph regularity method: Difference between revisions

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* <math> \mathcal{P}^{(1)} = \{V_i \colon i \in [a_1]\} </math> is equitable vertex partition of <math> V </math>. That is <math> |V_1| \leq \ldots \leq |V_{a_1}| \leq | V_1| + 1 </math> .
* <math> \mathcal{P}^{(j)} </math> partitions <math> \mathcal{K}_j(\mathcal{G}^{(1)}) = K_{a_1}^{(j)}(V_1, \ldots, V_{a_1}) </math> so that if <math> P_1^{(j-1)}, \ldots, P_j^{(j-1)} \in \mathcal{P}^{(j-1)} </math> and <math> \mathcal{K}_j(\cup_{i=1}^jP_i^{(j-1)}) \neq \emptyset </math> then <math> \mathcal{K}_j(\cup_{i=1}^jP_i^{(j-1)}) </math> is partitioned into at most <math> a_j </math> parts, all of which are members <math> \mathcal{P}^{(j)} </math>.
 
* For all but at most <math> \mu n^k </math> <math> k </math>-tuples <math> K \in \binom{V}{k} </math> there is unique <math> (\delta, \mathbf{d},r) </math>-regular <math> (k, k-1) </math>-complex <math> \mathbf{P} = \{P^{(j)}\}_{j=1}^{k-1} </math> such that <math> P^{(j)} </math> has as members <math> \binom{k}{j} </math> different partition classes from <math> \mathcal{P}^{(j)} </math> and <math> K \in \mathcal{K}_k(P^{(k-1)}) \subset \ldots \subset \mathcal{K}_k(P^{(1)}) </math>.</blockquote>Finally, the following defines what it means for a <math> k </math>-uniform hypergraph to be regular with respect to a partition. In particular, this is the main definition that describes the output of hypergraph regularity lemma below.<blockquote>'''Definition [Regularity with respect to a partition].''' We say that a <math> k </math>-graph <math> \mathcal{H}^{(k)} </math> is <math> (\delta_k, r) </math>-regular with respect to a family of partitions <math> \mathcal{P} </math> if all but at most <math> \delta_k n^k </math> <math> k- </math>edges <math> K </math> of <math> \mathcal{H}^{(k)} </math> have the property that <math> K \in \mathcal{K}_k(\mathcal{G}^{(1)}) </math> and if <math> \mathbf{P} = \{P^{(j)}\}_{j=1}^{k-1} </math> is unique <math> (k, k-1) </math>-complex for which <math> K \in \mathcal{K}_k(P^{(k-1)}) </math>, then <math> \mathcal{H}^{(k)} </math> is <math> (\delta_k, d(\mathcal{H}^{(k)} \vert P^{(k-1)}), r) </math> regular with respect to <math> \mathcal{P} </math>.</blockquote>