Diffuse reflection: Difference between revisions

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Restored revision 1038606838 by JoeNMLC (talk): Copyvio
Not really accurate or useful to say. Mirrors are not invisible. You can see a mirrored object just fine under most conditions.
 
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}}</ref> The rays represent [[luminous intensity]], which varies according to [[Lambert's cosine law]] for an ideal diffuse reflector.
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'''Diffuse reflection''' is the [[reflection (physics)|reflection]] of [[light]] or other [[radiationWave|waves]] or [[particles]] from a surface such that a [[ray (optics)|ray]] incident on the surface is [[scattering|scattered]] at many [[angle]]s rather than at just one angle as in the case of [[specular reflection]]. An ''ideal'' diffuse reflecting surface is said to exhibit [[Lambertian reflection]], meaning that there is equal [[luminance]] when viewed from all directions lying in the [[half-space (geometry)|half-space]] adjacent to the surface.
 
A surface built from a non-absorbing powder such as [[plaster]], or from fibers such as paper, or from a [[polycrystalline]] material such as white [[marble]], reflects light diffusely with great efficiency. Many common materials exhibit a mixture of specular and diffuse reflection.
 
The visibility of objects, excluding light-emitting ones, is primarily caused by diffuse reflection of light: it is diffusely-scattered light that forms the image of the object in thean observer's eye over a wide range of angles of the observer with respect to the object.
 
==Mechanism==
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Diffuse reflection from solids is generally not due to surface roughness. A flat surface is indeed required to give specular reflection, but it does not prevent diffuse reflection. A piece of highly polished white marble remains white; no amount of polishing will turn it into a mirror. Polishing produces some specular reflection, but the remaining light continues to be diffusely reflected.
 
The most general mechanism by which a surface gives diffuse reflection does not involve ''exactly'' the surface: most of the light is contributed by [[Subsurface scattering|scattering centers beneath the surface]],<ref>P.Hanrahan and W.Krueger (1993), ''Reflection from layered surfaces due to subsurface scattering'', in [http://www.cs.berkeley.edu/~ravir/6998/papers/p165-hanrahan.pdf SIGGRAPH ’93 Proceedings, J. T. Kajiya, Ed., vol.&nbsp;27, pp.&nbsp;165–174] {{webarchive|url=https://web.archive.org/web/20100727005751/http://www.cs.berkeley.edu/~ravir/6998/papers/p165-hanrahan.pdf |date=2010-07-27 }}.</ref><ref>H.W.Jensen et al. (2001), ''A practical model for subsurface light transport'', in '[http://www.cs.berkeley.edu/~ravir/6998/papers/p511-jensen.pdf Proceedings of ACM SIGGRAPH 2001', pp.&nbsp;511–518] {{webarchive|url=https://web.archive.org/web/20100727005456/http://www.cs.berkeley.edu/~ravir/6998/papers/p511-jensen.pdf |date=2010-07-27 }}</ref> as illustrated in Figure&nbsp;1.
If one were to imagine that the figure represents snow, and that the polygons are its (transparent) ice crystallites, an impinging ray is partially reflected (a few percent) by the first particle, enters in it, is again reflected by the interface with the second particle, enters in it, impinges on the third, and so on, generating a series of "primary" scattered rays in random directions, which, in turn, through the same mechanism, generate a large number of "secondary" scattered rays, which generate "tertiary" rays, and so forth.<ref>Only primary and secondary rays are represented in the figure.</ref> All these rays walk through the snow crystallites, which do not absorb light, until they arrive at the surface and exit in random directions.<ref>Or, if the object is thin, it can exit from the opposite surface, giving diffuse transmitted light.</ref> The result is that the light that was sent out is returned in all directions, so that snow is white despite being made of transparent material (ice crystals).
 
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|page=381
|year=1926
|author-link=Milton Kerker
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Exceptions include objects with polished (specularly reflecting) surfaces, and objects that themselves emit light. [[Rayleigh scattering]] is responsible for the blue color of the sky, and [[Mie scattering]] for the white color of the water droplets in clouds.
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{{DEFAULTSORT:Diffuse Reflection}}
[[Category:OpticsOptical phenomena]]
[[Category:Shading]]