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m in parallel axis theorem of mass moment of inertia, the parallel axis is parallel to the axis passes through the centre of mass of the body instead of its centre of gravity. |
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{{Short description|Theorem in planar dynamics}}
{{Redirect-distinguish|Steiner's theorem|Steiner's theorem (geometry)}}
The '''parallel axis theorem''', also known as '''Huygens–Steiner theorem''', or just as '''Steiner's theorem''',<ref>{{
==Mass moment of inertia==
[[File:Steiner.png|thumb|right|The mass moment of inertia of a body around an axis can be determined from the mass moment of inertia around a parallel axis through the
Suppose a body of mass {{math|''m''}} is rotated about an axis {{math|''z''}} passing through the body's [[
The parallel axis theorem states that if the body is made to rotate instead about a new axis {{math|''z′''}}, which is parallel to the first axis and displaced from it by a distance {{math|''d''}}, then the moment of inertia {{math|''I''}} with respect to the new axis is related to {{math|''I''<sub>cm</sub>}} by
:<math> I = I_\mathrm{cm} + md^2.</math>
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===Derivation===
We may assume, without loss of generality, that in a [[Cartesian coordinate system]] the perpendicular distance between the axes lies along the ''x''-axis and that the center of mass lies at the origin. The moment of inertia relative to the ''z''-axis is then
:<math>I_\mathrm{cm} = \int (x^2 + y^2) \, dm.</math>
The moment of inertia relative to the axis {{math|''z′''}}, which is
:<math>I = \int \left[(x
Expanding the brackets yields
:<math>I = \int (x^2 + y^2) \, dm + D^2 \int dm
The first term is {{math|''I''<sub>cm</sub>}} and the second term becomes {{math|''
:<math> I = I_\mathrm{cm} +
=== Tensor generalization ===
The parallel axis theorem can be generalized to calculations involving the [[Moment of inertia#
| last = Abdulghany | first = A. R.
| date = October 2017
| doi = 10.1119/1.4994835
| issue = 10
| journal = American Journal of Physics
| pages = 791–795
| title = Generalization of parallel axis theorem for rotational inertia
| volume = 85| doi-access = free
| bibcode = 2017AmJPh..85..791A
}}</ref> Let {{math|''I<sub>ij</sub>''}} denote the inertia tensor of a body as calculated at the center of mass. Then the inertia tensor {{math|''J<sub>ij</sub>''}} as calculated relative to a new point is
:<math>J_{ij}=I_{ij} + m\left(|\mathbf{R}|^2 \delta_{ij}-R_i R_j\right),</math>
where <math>\mathbf{R}=R_1\mathbf{\hat{x}}+R_2\mathbf{\hat{y}}+R_3\mathbf{\hat{z}}\!</math> is the displacement vector from the
For diagonal elements (when {{math|''i'' {{=}} ''j''}}), displacements perpendicular to the axis of rotation results in the above simplified version of the parallel axis theorem.
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where '''E'''<sub>3</sub> is the {{nobr|3 × 3}} [[identity matrix]] and <math>\otimes</math> is the [[outer product]].
Further generalization of the parallel axis theorem gives the inertia tensor about any set of orthogonal axes parallel to the reference set of axes x, y and z, associated with the reference inertia tensor, whether or not they pass through the center of mass.<ref name="Abdulghany"/>
:<math> I_{F} = I_\mathrm{ref} + m(M[\mathbf{R},\mathbf{R}] - 2M[\mathbf{R},\mathbf{C}])</math>
where <math>\mathbf{C}</math> is the vector from the initial reference point to the object's center of mass and <math>\mathbf{R}</math> is the vector from the initial reference point to the final reference point (<math>\mathbf{R}_F = \mathbf{R}_{ref} + \mathbf{R}</math>). The relational matrix is given by
:<math> M[\mathbf{r},\mathbf{c}] = \left[\begin{array}{rrr}(r_y c_y + r_z c_z) & -1/2(r_x c_y + r_y c_x) & -1/2(r_x c_z + r_z c_x) \\
-1/2(r_x c_y + r_y c_x) & (r_x c_x + r_z c_z) & -1/2(r_y c_z + r_z c_y) \\
-1/2(r_x c_z + r_z c_x) & -1/2(r_y c_z + r_y c_z) & (r_x c_x + r_y c_y) \end{array}\right] </math>
==Second moment of area==
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:<math> I_S = I_R + Md^2, \, </math>
which is known as the parallel axis theorem.<ref>{{Citation |first=Burton |last=Paul |year=1979 |title=Kinematics and Dynamics of Planar Machinery |publisher=[[Prentice Hall]] |isbn=978-0-13-516062-6
==Moment of inertia matrix==
The inertia matrix of a rigid system of particles depends on the choice of the reference point.<ref name="Kane">{{citation|first1=T. R.
Consider the inertia matrix [I<sub>S</sub>] obtained for a rigid system of particles measured relative to a reference point '''S''', given by
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y^2+z^2 & -xy & -xz \\ -y x & x^2+z^2 & -yz \\ -zx & -zy & x^2+y^2 \end{bmatrix}.</math>
This product can be computed using the matrix formed by the outer product ['''R''' '''R'''<sup>T</sup>] using the
:<math> -[R]^2 = |\mathbf{R}|^2[E_3] -[\mathbf{R}\mathbf{R}^T]=
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[[Category:Mechanics]]
[[Category:Physics theorems]]
[[Category:
[[fr:Moment d'inertie#Théorème de transport (ou théorème d'Huygens
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