Quaternionic analysis: Difference between revisions

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{{Short description|StudyFunction oftheory analyticwith functionsquaternion of quaternions, generalizing complex analysisvariable}}
 
In [[mathematics]], '''quaternionic analysis''' is the study of [[function (mathematics)|functions]] with [[quaternion]]s as the [[___domain of a function|___domain]] and/or range. Such functions can be called '''functions of a quaternion variable''' just as [[Function of a real variable|functions of a real variable]] or a [[Function of a complex variable|complex variable]] are called.
 
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An important example of a function of a quaternion variable is
:<math>f_1(q) = u q u^{-1}</math>
which [[quaternions and spatial rotation|rotates the vector part of ''q'']] by twice the angle represented by the versor ''u''.
 
The quaternion [[multiplicative inverse]] <math>f_2(q) = q^{-1}</math> is another fundamental function, but as with other number systems, <math>f_2(0)</math> and related problems are generally excluded due to the nature of [[dividing by zero]].
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== The derivative for quaternions ==
Since the time of Hamilton, it has been realized that requiring the independence of the [[derivative]] from the path that a differential follows toward zero is too restrictive: it excludes even <math>\ f(q) = q^2\ </math> from differentiation. Therefore, a direction-dependent derivative is necessary for functions of a quaternion variable.<ref>{{harvharvp|Hamilton|1866|loc=Chapter &nbsp;II, On differentials and developments of functions of quaternions, pp. &nbsp;391–495 }}</ref><ref>{{harvharvp|Laisant|1881|loc=Chapitre &nbsp;5: Différentiation des Quaternions, pp. &nbsp;104–117 }}</ref>
Considering the increment of [[polynomial function]] of quaternionic argument shows that the increment is a linear map of increment of the argument. {{Dubious|date=March 2019}} From this, a definition can be made:
 
A continuous mapfunction
<math>\ f: \mathbb H \rightarrow \mathbb H\ </math>
is called ''differentiable on the set'' <math>\ U \subset \mathbb H\ ,</math>, if, at every point <math>\ x \in U\ ,</math>, thean increment of the mapfunction <math>\ f\ </math> corresponding to a quaternion increment <math>\ h\ </math> of its argument, can be represented as
: <math> f(x+h) - f(x) = \frac{\operatorname d f(x)}{\operatorname d x} \circ h + o(h)</math>
where
: <math>\frac{\operatorname d f(x)}{\operatorname d x}:\mathbb H\rightarrow\mathbb H</math>
is [[linear map]] of quaternion algebra <math>\ \mathbb H\ ,</math> and
<math>\ o:\mathbb H\rightarrow \mathbb H\ </math>
isrepresents suchsome continuous map such that
: <math>\lim_{a \rightarrow 0} \frac{\ \left|\ o(a)\ \right|\ }{ \left|\ a\ \right| } = 0\ ,</math>
and the notation <math>\ \circ h\ </math> denotes ...{{explain|date=September 2024}}
 
The linear map
<math>\frac{\operatorname d f(x)}{\operatorname d x}</math>
is called the derivative of the map <math>\ f ~.</math>.
 
On the quaternions, the derivative may be expressed as
: <math>\frac{\operatorname d f(x)}{\operatorname d x} = \sum_s \frac{d_\operatorname{d}_{s0} f(x)}{\operatorname d x} \otimes \frac{d_\operatorname{d}_{s1} f(x)}{\operatorname d x} </math>
Therefore, the differential of the map <math>\ f\ </math> may be expressed as follows, with brackets on either side.
:<math>\frac{\operatorname d f(x)}{\operatorname d x}\circ dx\operatorname d x = \left(\sum_s \frac{d_\operatorname{d}_{s0} f(x)}{\operatorname d x} \otimes \frac{d_\operatorname{d}_{s1} f(x)}{\operatorname d x}\right)\circ dx\operatorname d x = \sum_s \frac{d_\operatorname{d}_{s0} f(x)}{\operatorname d x} dx\left( \operatorname d x \right) \frac{d_\operatorname{d}_{s1} f(x)}{\operatorname d x}</math>
 
The number of terms in the sum will depend on the function ''<math>\ f'' ~.</math> The expressions
<math>~~ \frac{d_\operatorname{d}_{sp}\operatorname d f(x)}{\operatorname d x}, ~~ \mathsf{\ for\ } ~~ p = 0, 1 ~~</math> are called
components of derivative.
 
The derivative of a quaternionic function holdsis thedefined followingby the equalitiesexpression
: <math>\frac{df\operatorname d f(x)}{\operatorname d x}\circ h = \lim_{t\to 0}\left(t^\ \frac{-1}(\ f(x +th t\ h) - f(x))\ }{ t }\ \right)</math>
where the variable <math>\ t\ </math> is a real scalar.
 
The following equations then hold:
: <math>\frac{\operatorname d\left( f(x) + g(x) \right)}{\operatorname d x} = \frac{df\operatorname d f(x)}{\operatorname d x} + \frac{dg\operatorname d g(x)}{\operatorname d x}</math>
 
: <math>\frac{df\operatorname d\left( f(x)\ g(x)\right)}{\operatorname d x} = \frac{df\operatorname d f(x) }{\operatorname d x}\ g(x) + f(x)\ \frac{dg\operatorname d g(x)}{\operatorname d x}</math>
 
: <math>\frac{df\operatorname d \left( f(x)\ g(x)\right)}{\operatorname d x} \circ h = \left(\frac{df\operatorname d f(x)}{\operatorname d x}\circ h\right )\ g(x) + f(x) \left(\frac{dg\operatorname d g(x)}{\operatorname d x}\circ h\right)</math>
 
: <math>\frac{daf\operatorname d \left( a\ f(x)\ b\right)}{\operatorname d x} = a\ \frac{df\operatorname d f(x)}{\operatorname d x}\ b</math>
 
: <math>\frac{daf\operatorname d \left( a\ f(x)\ b\right)}{\operatorname d x}\circ h = a \left(\frac{df\operatorname d f(x)}{\operatorname d x}\circ h\right) b</math>
 
For the function ''<math>\ f''(''x'') = ''axb''a\ x\ b\ ,</math> where <math>\ a\ </math> and <math>\ b\ </math> are constant quaternions, the derivative is
{| class="wikitable"
|-
| <math> \frac{daxb\operatorname d \left( a\ x\ b \right)}{\operatorname d x} = a \otimes b </math>
|style="background:white;"| &emsp;
|
| <math>dy \operatorname d y=\frac{daxb\operatorname d \left(a\ x\ b\right)}{\operatorname d x} \circ dx\operatorname d x = a\,dx \,left(\operatorname d x\right)\ b</math>
|}
 
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{| class="wikitable"
|-
| <math> \frac{d_\operatorname{d}_{10} axb\left(a\ x\ b\right)}{\operatorname d x} = a </math>
|style="background:white;"| &emsp;
|
| <math> \frac{d_\operatorname{d}_{11} axb\left(a\ x\ b\right)}{\operatorname d x} = b </math>
|}
 
Similarly, for the function ''<math>\ f''(''x'') = ''x<sup>^2\ ,</supmath>'', the derivative is
{| class="wikitable"
|-
| <math>\frac{dx\operatorname d x^2}{\operatorname d x}=x \otimes 1 + 1 \otimes x</math>
|style="background:white;"| &emsp;
|
| <math>dy\operatorname d y=\frac{dx\operatorname d x^2}{\operatorname d x}\circ dx\operatorname d x = x\,dx \operatorname d x +dx (\,operatorname d x)\ x </math>
|}
 
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{| class="wikitable"
|-
| <math> \frac{d_\operatorname{d}_{10} x^2 }{\operatorname d x} = x </math>
|style="background:white;"| &emsp;
|
| <math> \frac{d_\operatorname{d}_{11} x^2}{\operatorname d x} = 1 </math>
|-
| <math>\frac{d_\operatorname{d}_{20} x^2 }{\operatorname d x} = 1 </math>
|style="background:white;"| &emsp;
|
| <math>\frac{d_\operatorname{d}_{21} x^2}{\operatorname d x} = x </math>
|}
 
Finally, for the function '' <math>\ f''(''x'') = ''x''<sup>−1^{-1}\ ,</supmath>, the derivative is
{| class="wikitable"
|-
| <math> \frac{dx\operatorname d x^{-1} }{\operatorname d x} = -x^{-1} \otimes x^{-1}</math>
|style="background:white;"| &emsp;
|
| <math>dy \operatorname d y = \frac{dx\operatorname d x^{-1} }{\operatorname d x} \circ dx\operatorname d x = -x^{-1}dx(\,operatorname d x)\ x^{-1}</math>
|}
 
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{| class="wikitable"
|-
| <math>\frac{d_\operatorname{d}_{10} x^{-1} }{\operatorname d x} = -x^{-1} </math>
|style="background:white;"| &emsp;
|
| <math>\frac{d_\operatorname{d}_{11} x^{-1} }{\operatorname d x} = x^{-1} </math>
|}
 
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| year = 1995
| doi = 10.1070/RM1995v050n01ABEH001662
| zbl = 0848.58005}}| s2cid = 250897899
}}
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| zbl = 0399.30038| bibcode = 1979MPCPS..85..199S
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{{Analysis in topological vector spaces}}
{{AnalysisInTopologicalVectorSpaces}}
 
[[Category:Quaternions]]
[[Category:Functions and mappings]]
[[Category:Articles containing proofs]]
[[Category:Functions and mappings]]
[[Category:Quaternions|analysis]]