Gauss–Legendre algorithm: Difference between revisions

Revision as of 21:15, 10 June 2024

Latest revision as of 09:52, 15 June 2025

(5 intermediate revisions by 4 users not shown)

Line 7:

== Algorithm ==

# Initial value setting: <math display="block">a_0 = 1\qquad b_0 = \frac{1}{\sqrt{2}}\qquad p_0 = 1\qquad t_0 = \frac{1}{4}\qquad p_0 = 1.</math>

# Repeat the following instructions until the difference ofbetween <math>a_na_{n+1}</math> and <math>b_nb_{n+1}</math> is within the desired accuracy: <math display="block"> \begin{align}

a_{n+1} & = \frac{a_n + b_n}{2}, \\

\\

b_{n+1} & = \sqrt{a_n b_n}, \\

\\

t_p_{n+1} & = t_n - p_n(a_{n}-a_{n+1})^22p_n, \\

\\

p_{n+1} & = 2p_n.

\\

t_{n+1} & = t_n - p_n(a_{n+1}-a_{n})^2. \\

\end{align}

</math>

Line 26 ⟶ 25:

:<math>3.14159264\dots</math>

:<math>3.1415926535897932382\dots</math>

:<math>3.14159265358979323846264338327950288419711\dots</math>

:<math>3.141592653589793238462643383279502884197169399375105820974944592307816406286208998625\dots</math>

The algorithm has [[quadratic convergence]], which essentially means that the number of correct digits doubles with each [[iteration]] of the algorithm.

Line 108:

Legendre proved the following identity:

:<math display="block">K(\cos \theta) E(\sin \theta ) + K(\sin \theta ) E(\cos \theta) - K(\cos \theta) K(\sin \theta) = {\pi \over 2},</math>

for all <math>\theta</math>.<ref name="brent" />.

=== Elementary proof with integral calculus ===

The Gauss-Legendre algorithm can be proven to give results converging to π<math>\pi</math> using only integral calculus. This is done here<ref>{{citation|title=Recent Calculations of π: The Gauss-Salamin Algorithm|last1=Lord|first1=Nick|doi=10.2307/3619132|year=1992|journal=The Mathematical Gazette|volume=76|issue=476|pages=231–242|jstor=3619132|s2cid=125865215 }}</ref> and here.<ref>{{citation|title=Easy Proof of Three Recursive π-Algorithms|last1=Milla|first1=Lorenz|arxiv=1907.04110|year=2019}}</ref>

== See also ==