Graph factorization: Difference between revisions

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Undid revision 971246833 by 184.161.107.105 (talk) "is 2-factorable" means "can be partitioned into two perfect matchings", and does not mean "has a 2-factor"
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{{Short description|Partition of a graph into spanning subgraphs}}
{{Distinguish|Factor graph}}
 
[[Image:Desargues graph 3color edge.svg|thumb|200px|1-factorization of the [[Desargues graph]]: each color class is a {{nowrap|1-factor}}.]]
[[Image:Petersen-graph-factors.svg|right|thumb|200px|The [[Petersen graph]] can be partitioned into a {{nowrap|1-factor}} (red) and a {{nowrap|2-factor}} (blue). However, the graph is not {{nowrap|1-factorable}}.]]
{{unsolved|mathematics|'''Conjecture:''' If ''n'' is odd and ''k'' ≥ ''n'', then ''G'' is 1-factorable. If ''n'' is even and ''k'' ≥ ''n'' − 1 then ''G'' is 1-factorable.}}
In [[graph theory]], a '''factor''' of a [[graph (discrete mathematics)|graph]] ''G'' is a [[spanning subgraph]], i.e., a subgraph that has the same vertex set as ''G''. A '''''k''-factor''' of a graph is a spanning ''k''-[[Regular graph|regular]] subgraph, and a '''''k''-factorization''' partitions the edges of the graph into disjoint ''k''-factors. A graph ''G'' is said to be '''''k''-factorable''' if it admits a ''k''-factorization. In particular, a '''1-factor''' is a [[perfect matching]], and a 1-factorization of a ''k''-[[regular graph]] is ana [[edge coloring|proper edge coloring]] with ''k'' colors. A '''2-factor''' is a collection of disjoint [[Cyclecycle (graph theory)|cyclescycle]]s that spans all vertices of the graph.
 
==1-factorization==
 
If a graph is 1-factorable (ie, has a 1-factorization), then it has to be a [[regular graph]]. However, not all regular graphs are 1-factorable. A ''k''-regular graph is 1-factorable if it has [[chromatic index]] ''k''; examples of such graphs include:
* Any regular [[bipartite graph]].<ref>{{harvtxt|Harary|1969}}, Theorem 9.2, p. 85. {{harvtxt|Diestel|2005}}, Corollary 2.1.3, p. 37.</ref> [[Hall's marriage theorem]] can be used to show that a ''k''-regular bipartite graph contains a perfect matching. One can then remove the perfect matching to obtain a (''k''&nbsp;&minus;&nbsp;1)-regular bipartite graph, and apply the same reasoning repeatedly.
* Any [[complete graph]] with an [[parity (mathematics)|even]] number of nodes (see [[#Complete graphs|below]]).<ref>{{harvtxt|Harary|1969}}, Theorem 9.1, p. 85.</ref>
However, there are also ''k''-regular graphs that have chromatic index ''k''&nbsp;+&nbsp;1, and these graphs are not 1-factorable; examples of such graphs include:
* Any regular graph with an [[parity (mathematics)|odd]] number of nodes.
* The [[Petersen graph]].
 
===Complete graphs===
[[File:Complete-edge-coloring.svg|thumb|200px|1-factorization of ''K''<sub>8</sub> in which each {{nowrap|1-factor}} consists of an edge from the center to a vertex of a [[heptagon]] together with all possible perpendicular edges]]
A 1-factorization of a [[complete graph]] corresponds to pairings in a [[round-robin tournament]]. The 1-factorization of complete graphs is a special case of [[Baranyai's theorem]] concerning the 1-factorization of complete [[hypergraph]]s.
 
One method for constructing a 1-factorization of a complete graph on an even number of vertices involves placing all but one of the vertices on a circle, formingin a [[regular polygon]], with the remaining vertex at the center of the circle. With this arrangement of vertices, one way of constructing a 1-factor of the graph is to choose an edge ''e'' from the center to a single polygon vertex together with all possible edges that lie on lines perpendicular to ''e''. The 1-factors that can be constructed in this way form a 1-factorization of the graph.
 
The number of distinct 1-factorizations of ''K''<sub>2</sub>, ''K''<sub>4</sub>, ''K''<sub>6</sub>, ''K''<sub>8</sub>, ... is 1, 1, 6, 6240, 1225566720, 252282619805368320, 98758655816833727741338583040, ... ({{oeis|A000438}}).
 
===1-factorization conjecture===
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* If ''k''&nbsp;=&nbsp;2''n''&nbsp;&minus;&nbsp;1, then ''G'' is the complete graph ''K''<sub>2''n''</sub>, and hence 1-factorable (see [[#Complete graphs|above]]).
* If ''k''&nbsp;=&nbsp;2''n''&nbsp;&minus;&nbsp;2, then ''G'' can be constructed by removing a perfect matching from ''K''<sub>2''n''</sub>. Again, ''G'' is 1-factorable.
* {{harvtxt|Chetwynd|Hilton|1985}} show that if ''k''&nbsp;≥&nbsp;12n12''n''/7, then ''G'' is 1-factorable.
The '''1-factorization conjecture'''<ref>{{harvtxt|Chetwynd|Hilton|1985}}. {{harvtxt|Niessen|1994}}. {{harvtxt|Perkovic|Reed|1997}}. [[#West1FC|West]].</ref> is a long-standing [[conjecture]] that states that ''k''&nbsp;≈&nbsp;''n'' is sufficient. In precise terms, the conjecture is:
* If ''n'' is odd and ''k''&nbsp;≥&nbsp;''n'', then ''G'' is 1-factorable. If ''n'' is even and ''k''&nbsp;≥&nbsp;''n''&nbsp;&minus;&nbsp;1 then ''G'' is 1-factorable.
The [[overfull conjecture]] implies the 1-factorization conjecture.
The conjecture was confirmed by Csaba, Kühn, Lo, Osthus and Treglown for sufficiently large ''n''.<ref name="csaba">
{{Citation
| last1 = Csaba
| first1 = Béla
| last2 = Kühn
| first2 = Daniela
| last3 = Lo
| first3 = Allan
| last4 = Osthus
| first4 = Deryk
| last5 = Treglown
| first5 = Andrew
 
| title = Proof of the 1-factorization and Hamilton decomposition conjectures
| journal = Memoirs of the American Mathematical Society
| date = June 2016
| doi = 10.1090/memo/1154
}}.
</ref>
 
===Perfect 1-factorization===
A '''perfect pair''' from a 1-factorization is a pair of 1-factors whose union [[Glossary_of_graph_theoryGlossary of graph theory#Subgraphs|induces]] a [[Hamiltonian cycle]].
 
A '''perfect 1-factorization''' (P1F) of a graph is a 1-factorization having the property that every pair of 1-factors is a perfect pair. A perfect 1-factorization should not be confused with a perfect matching (also called a 1-factor).
 
In 1964, [[Anton Kotzig]] conjectured that every [[complete graph]] ''K''<sub>2''n''</sub> where ''n'' ≥ 2 has a perfect 1-factorization. So far, it is known that the following graphs have a perfect 1-factorization:<ref name="wallis">
{{Citation
| first = W. D. | last = Wallis
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</ref>
 
* the infinite family of complete graphs ''K''<sub>2''p''</sub> where ''p'' is an odd [[prime number|prime]] (by Anderson and also Nakamura, independently),
* the infinite family of complete graphs ''K''<sub>''p'' + 1</sub> where ''p'' is an odd prime,
* and sporadic additional results, including ''K''<sub>2''n''</sub> where 2''n'' ∈ {16, 28, 36, 40, 50, 126, 170, 244, 344, 730, 1332, 1370, 1850, 2198, 3126, 6860, 12168, 16808, 29792}. Some newer results are collected [http://users.monash.edu.au/~iwanless/data/P1F/newP1F.html here].
<!-- Related OEIS sequences: A005702 A120488 A120489 -->
 
If the complete graph ''K''<sub>''n'' + 1</sub> has a perfect 1-factorization, then the [[complete bipartite graph]] ''K''<sub>''n'',''n''</sub> also has a perfect 1-factorization.<ref name="wanless">
{{Citation
| last1 = Bryant
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| issn = 0097-3165
| doi = 10.1006/jcta.2001.3240
| doi-access= free
}}
</ref>
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==2-factorization==
 
If a graph is 2-factorable, then it has to be 2''k''-regular for some integer ''k''. [[Julius Petersen]] showed in 1891 that this necessary condition is also sufficient: [[2-factor theorem|any 2''k''-regular graph is 2-factorable]].<ref>{{harvtxt|Petersen|1891}}, §9, p. 200. {{harvtxt|Harary|1969}}, Theorem 9.9, p. 90. See {{harvtxt|Diestel|2005}}, Corollary 2.1.5, p. 39 for a proof.</ref>
 
If a [[connectivity (graph theory)|connected graph]] is 2''k''-regular and has an even number of edges it may also be ''k''-factored, by choosing each of the two factors to be an alternating subset of the edges of an [[Euler tour]].<ref>{{harvtxt|Petersen|1891}}, §6, p. 198.</ref> This applies only to connected graphs; disconnected counterexamples[[counterexample]]s include disjoint unions of odd cycles, or of copies of ''K''<sub>2''k''+1</sub>.
 
The [[Oberwolfach problem]] concerns the existence of 2-factorizations of [[complete graph]]sgraphs into [[graph isomorphism|isomorphic]] subgraphs. It asks for which subgraphs this is possible. This is known when the subgraph is connected (in which case it is a [[Hamiltonian cycle]] and this special case is the problem of [[Hamiltonian decomposition]]) but the general case remains unsolved[[open problem|open]].
 
==NotesReferences==
{{reflist}}
 
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}}
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{{refbegin}}
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{{refend}}
 
[[Category:Graph theory objects]]
[[Category:Factorization]]