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! style="background: f5f5f5;" |'''Proof that the number generated is {{sqrt|2}} − 1'''
|- style="text-align: left; vertical-align: top; background: white"
| style="padding-left: 1em; padding-right: 1em" |The proof uses [[Farey sequence]]s and [[simple continued
Cantor's construction produces mediants because the rational numbers were sequenced by increasing denominator. The first interval in the table is <math>(\frac{1}{3}, \frac{1}{2}).</math> Since <math>\frac{1}{3}</math> and <math>\frac{1}{2}</math> are adjacent in <math>F_3,</math> their mediant <math>\frac{2}{5}</math> is the first fraction in the sequence between <math>\frac{1}{3}</math> and <math>\frac{1}{2}.</math> Hence, <math>\frac{1}{3} < \frac{2}{5} < \frac{1}{2}.</math> In this inequality, <math>\frac{1}{2}</math> has the smallest denominator, so the second fraction is the mediant of <math>\frac{2}{5}</math> and <math>\frac{1}{2},</math> which equals <math>\frac{3}{7}.</math> This implies: <math>\frac{1}{3} < \frac{2}{5} < \frac{3}{7} < \frac{1}{2}.</math> Therefore, the next interval is <math>(\frac{2}{5}, \frac{3}{7}).</math>
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| publisher = Simon & Schuster
| ___location = New York
| year = 1937}}. Reprinted, 1984, {{isbn|978-0-671-62818-5}}.
* {{Citation | first1 = Garrett
| last1 = Birkhoff
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| publisher = Macmillan
| ___location = New York
| year = 1941}}. Reprinted, Taylor & Francis, 1997, {{isbn|978-1-56881-068-3}}.
* {{Citation | last = Burton
| first = David M.
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| journal = Journal für die Reine und Angewandte Mathematik
| year = 1878| doi = 10.1515/crll.1878.84.242
| doi-broken-date =
}}.
* {{Citation | first = Georg
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| ___location = Oxford
| year = 1938
* {{Citation | last = Havil
| first = Julian
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|volume = I
|publisher = Addison-Wesley
|___location = Reading,
|year = 1956
}}. ([https://archive.org/details/topicsinnumberth0000leve Reprinted by Dover Publications], 2002, {{isbn|978-0-486-42539-9}}.)
* {{Citation | editor-last = Noether
| editor-first = Emmy
|