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{{Short description|Tensor invariant under permutations of vectors it acts on}}
{{Use American English|date = February 2019}}
In [[mathematics]], a '''symmetric tensor''' is
:<math>T(v_1,v_2,\ldots,v_r) = T(v_{\sigma 1},v_{\sigma 2},\ldots,v_{\sigma r})</math>
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==Examples==
Many [[material properties]] and [[field (physics)|fields]] used in physics and engineering can be represented as symmetric tensor fields; for example: [[stress (physics)|stress]], [[strain tensor|strain]], and [[anisotropic]] [[Electrical resistivity and conductivity|conductivity]]. Also, in [[diffusion MRI]] one often uses symmetric tensors to describe diffusion in the brain or other parts of the body.
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Ellipsoids are examples of [[algebraic varieties]]; and so, for general rank, symmetric tensors, in the guise of [[homogeneous polynomial]]s, are used to define [[projective varieties]], and are often studied as such.
Given a [[Riemannian manifold]] <math>(M,g)</math> equipped with its Levi-Civita connection <math>\nabla</math>, the [[Riemann curvature tensor#Coordinate expression|covariant curvature tensor]] is a symmetric order 2 tensor over the vector space <math display="inline">V = \Omega^2(M) = \bigwedge^2 T^*M</math> of differential 2-forms.
==Symmetric part of a tensor==
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For symmetric tensors of arbitrary order ''k'', decompositions
:<math>T = \sum_{i=1}^r \lambda_i \, v_i^{\otimes k}</math>
are also possible. The minimum number ''r'' for which such a decomposition is possible is the ''symmetric'' [[Tensor (intrinsic definition)#Tensor rank|rank]] of ''T''.<ref name="Comon2008">{{Cite journal | last1 = Comon | first1 = P. | last2 = Golub | first2 = G. | last3 = Lim | first3 = L. H. | last4 = Mourrain | first4 = B. | title = Symmetric Tensors and Symmetric Tensor Rank | doi = 10.1137/060661569 | journal = SIAM Journal on Matrix Analysis and Applications | volume = 30 | issue = 3 | pages = 1254 | year = 2008 | arxiv = 0802.1681 | s2cid = 5676548 }}</ref> This minimal decomposition is called a Waring decomposition; it is a symmetric form of the [[tensor rank decomposition]]. For second-order tensors this corresponds to the rank of the matrix representing the tensor in any basis, and it is well known that the maximum rank is equal to the dimension of the underlying vector space. However, for higher orders this need not hold: the rank can be higher than the number of dimensions in the underlying vector space. Moreover, the rank and symmetric rank of a symmetric tensor may differ.<ref>{{Cite journal|last=Shitov|first=Yaroslav|date=2018|title=A Counterexample to Comon's Conjecture|url=https://epubs.siam.org/action/captchaChallenge?redirectUri=%2Fdoi%2F10.1137%2F17M1131970|journal=SIAM Journal on Applied Algebra and Geometry|language=en-US|volume=2|issue=3|pages=428–443|doi=10.1137/17m1131970|issn=2470-6566|arxiv=1705.08740|s2cid=119717133 }}</ref>
==See also==
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