Pascal's triangle: Difference between revisions

Content deleted Content added
Altered journal. | Use this tool. Report bugs. | #UCB_Gadget
To arbitrary bases: refined congruence phrasing
 
(3 intermediate revisions by 3 users not shown)
Line 458:
| doi = 10.5802/ambp.211
| url = https://ambp.centre-mersenne.org/item/10.5802/ambp.211.pdf
}}.</ref> as demonstrated [[#Binomial expansions|above]]. Thus, when the entries of the row are concatenated and read in radix <math>a</math> they form the numerical equivalent of <math>(a + 1)^{n} = 11^{n}_{a}</math>. If <math>c = a + 1</math> for <math>c < 0</math>, then the theorem [[Negative base|holds]] for <math>a =\bmod 2c</math>, with <math>a</math> congruent to <math>\{c - 1, -(c + 1)\} \;\mathrm{mod}\; 2c</math>, and with odd values of <math>n</math> [[Negative number#Multiplication|yielding]] negative row products.<ref>{{cite book
| display-authors = etal
| last = Hilton | first = P.