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===Functional equation===
''The exponential satisfies the [[functional equation]]:''
<math display=block>\exp(x+y)= \exp(x)\cdot \exp(y).</math>
This results from the uniqueness and the fact that the function
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The two first characterizations are equivalent, since, if {{tmath|1=b=e^k}} and {{tmath|1= k=\ln b}}, one has
The basic properties of the exponential function (derivative and functional equation) implies immediately the third and
Suppose that the third condition is verified, and let {{tmath|k}} be the constant value of <math>f'(x)/f(x).</math> Since <math display = inline>\frac {\partial e^{kx}}{\partial x}=ke^{kx},</math> the [[quotient rule]] for derivation
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<math display="block">e^z = \lim_{n\to\infty}\left(1+\frac{z}{n}\right)^n</math>
As with the real exponential function (see {{slink||Functional equation}} above), the complex exponential satisfies the functional equation
<math display=
Among complex functions, it is the unique solution which is [[holomorphic]] at the point {{tmath|1= z = 0}} and takes the derivative {{tmath|1}} there.<ref>{{cite book |last=Hille |first=Einar |year=1959 |title=Analytic Function Theory |volume=1 |place=Waltham, MA |publisher=Blaisdell |chapter=The exponential function |at=§ 6.1, {{pgs|138–143}} }}</ref>
The [[complex logarithm]] is a [[left inverse function|right-inverse function ]] of the complex exponential:
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<math display="block">\overline{e^z}=e^{\overline z}.</math>
Its modulus is
<math display="block">|e^z|= e^{
where {{tmath|\Re(z)}} denotes the real part of {{tmath|z}}.
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<math display="block">e^{it} =\cos(t)+i\sin(t). </math>
This formula provides the decomposition of complex
<math display="block">e^{x+iy} = e^{x}e^{iy} = e^x\,\cos y + i e^x\,\sin y.</math>
The trigonometric functions can be expressed in terms of complex exponentials:
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