User:Tardis/regdiff.py: Difference between revisions

Revision as of 23:04, 9 November 2008

Latest revision as of 17:41, 10 June 2022

(One intermediate revision by one other user not shown)

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<sourcesyntaxhighlight lang="python">

#!/usr/bin/env python

#regdiff.py

#Created November 9 2008

#Updated November 910 2008

#Version 0.3.1

#This program is free software; you can redistribute it and/or modify it under

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#The output deletes all keys and values present in the first but not in the

#second! Therefore, this should be run only on exports of complete subtrees.

#The input must be sorted (values sorted within each key); I believe that

#Regedit's export does this, and will also guarantee complete subtrees.

#It's probably wise to double check any key removals in the output: look for

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# - verify continuous progress

# - support displaying progress

#Version 0.3.1, November 10 2008:

# - use case-insensitive and subkey-aware comparisons for ordering

#Bugs:

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#I don't know whether .REG files are really UTF-16 or UCS-2.

#I'm not sure that the last blank line is really necessary; a trailing CRLF

#may be sufficient.

import sys,codecs

def keycompare(a,b):

"""Return an integer indicating the ordering of keys a and b."""

return cmp(a.lower().split('\\'),b.lower().split('\\'))

class line(object):

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self.delete=s[1]=='-'

self.lastkey=self.name=s[1+self.delete:-3] # ends in "]\r\n"

if k is not None and self.lastkey<k.lastkey: is not None and\

keycompare(self.lastkey,k.lastkey)<0:

raise ValueError,"key %r precedes %r in input"%\

(k.lastkey,self.lastkey)

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elif c=='"': break

else: raise IOError,"unterminated name in "+repr(s)

elif s[0]=!='@': passraise #IOError,"unrecognized key'format: "+repr(s default value)

else: raise IOError,"unrecognized format: "+repr(s)

# The name for @ is "", which properly sorts before everything.

self.name=s[1:index-1]

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else:

self.lastkey=k.lastkey

if not k.iskey and self.name.lower()<k.name.lower():

raise ValueError,"value %r precedes %r in input"%\

(k.name,self.name)

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# values (since the values go with a previous key), and EOF comes after

# everything. Positive values mean that n comes first.

c=o.eof-n.eof or cmpkeycompare(o.lastkey,n.lastkey) or\

o.iskey-n.iskey or cmp(o.name.lower(),n.name.lower())

o.old=c<=0

n.old=c>=0

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out.write("\r\n")

if displayProgress: sys.stderr.write('\n')

</syntaxhighlight>

</source>