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Note that finding the middle element is also two-pass |
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Given any list as an input:
* Find the ''n''th element from the end (or report that the list has fewer than ''n'' elements).
* Find the middle element of the list. However, this is solvable with two passes: Pass 1 counts the elements and pass 2 picks out the middle one.
Given a list of numbers:
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* Find the [[mode (statistics)|modes]] (This is not the same as finding the most frequent symbol from a limited alphabet).
* Sort the list.
* Count the number of items greater than or less than the [[mean]]. However, this can be done in constant memory with two passes: Pass 1 finds the average and pass 2 does the counting.
The two-pass == References==
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