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{{short description|Branch of hydraulics and fluid mechanics}}
'''Open-channel flow''', a branch of [[hydraulics]] and [[fluid mechanics]], is a type of [[liquid]] flow within a conduit or in channel with a free surface, known as a [[Stream channel|channel]].<ref>{{Cite book|last=Chow|first=Ven Te|url=https://heidarpour.iut.ac.ir/sites/heidarpour.iut.ac.ir/files/u32/open-chow.pdf|title=Open-Channel Hydraulics|publisher=The Blackburn Press|year=2008|isbn=978-1932846188|___location=Caldwell, NJ}}</ref><ref>{{Cite book|last=Battjes|first=Jurjen A.|url=https://www.cambridge.org/core/books/unsteady-flow-in-open-channels/5CCE099F37BCC5AF4E67B35F15666E7B|title=Unsteady Flow in Open Channels|last2=Labeur|first2=Robert Jan|publisher=Cambridge University Press|year=2017|isbn=9781316576878|___location=Cambridge, UK}}</ref> The other type of flow within a conduit is [[pipe flow]]. These two types of flow are similar in many ways but differ in one important respect: the free surface. Open-channel flow has a [[free surface]], whereas pipe flow does not.
[[File:Arizona cap canal.jpg|alt=|thumb|[[Central Arizona Project]] channel.]]
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***** The depth changes over a long distance.
** ''Continuous flow''
*** The discharge is constant throughout the [[
** ''Spatially-varied flow''
*** The discharge of a steady flow is non-uniform along a channel. This happens when water enters and/or leaves the channel along the course of flow. An example of flow entering a channel would be a road side gutter. An example of flow leaving a channel would be an irrigation channel. This flow can be described using the continuity equation for continuous unsteady flow requires the consideration of the time effect and includes a time element as a variable.
==States of flow==
The behavior of open-channel flow is governed by the effects of [[viscosity]] and gravity relative to the [[inertia
== Core equations ==
It is possible to formulate equations describing three [[
To simplify the final form of the equations, it is acceptable to make several assumptions:
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# The Reynolds number is sufficiently large such that viscous diffusion can be neglected
# The flow is one-dimensional across the x-axis
=== Continuity equation ===
The general [[continuity equation]], describing the conservation of mass, takes the form:<math display="block">{\partial \rho\over{\partial t}} + \nabla \cdot (\rho {\bf v}) = 0</math>where <math>\rho</math> is the fluid [[density]] and <math>\nabla \cdot()</math> is the [[divergence]] operator. Under the assumption of incompressible flow, with a constant [[control volume]] <math>V</math>, this equation has the simple expression <math>\nabla \cdot {\bf v} = 0</math>. However, it is possible that the [[Cross section (geometry)|cross-sectional area]] <math>A</math> can change with both time and space in the channel. If we start from the integral form of the continuity equation:<math display="block">{d\over{dt}}\int_{V}\rho \; dV = -\int_{V} \nabla\cdot(\rho {\bf v}) \; dV</math>it is possible to decompose the volume integral into a cross-section and length, which leads to the form:<math display="block">{d\over{dt}}\int_{x}\left(\int_{A}\rho \; dA \right) dx = -\int_{x}\left[\int_{A}\nabla\cdot(\rho {\bf v}) \; dA \right] dx</math>Under the assumption of incompressible, 1D flow, this equation becomes:<math display="block">{d\over{dt}}\int_{x}\left(\int_{A}dA \right) dx = -\int_{x}{\partial\over{\partial x}}\left(\int_{A} u \; dA \right) dx</math>By noting that <math>\int_{A}dA = A</math> and defining the [[volumetric flow rate]] <math>Q = \int_{A}u \; dA</math>, the equation is reduced to:<math display="block">\int_{x}{\partial A\over{\partial t}} \; dx = -\int_{x}{\partial Q\over{\partial x}} dx</math>Finally, this leads to the continuity equation for incompressible, 1D open-channel flow:<math display="block">{\partial A\over{\partial t}} + {\partial Q\over{\partial x}} = 0</math>
=== Momentum equation ===
The momentum equation for open-channel flow may be found by starting from the [[Incompressible navier-stokes equations|incompressible Navier-Stokes equations]] :<math display="block">\overbrace{\underbrace{{\partial {\bf v}\over{\partial t}}}_{\begin{smallmatrix} \text{Local} \\ \text{Change} \end{smallmatrix}} + \underbrace{{\bf v}\cdot\nabla {\bf v}}_{\text{Advection}}}^{\text{Inertial Acceleration}} = -\underbrace{{1\over{\rho}}\nabla p}_{\begin{smallmatrix} \text{Pressure} \\ \text{Gradient} \end{smallmatrix}} + \underbrace{\nu \Delta {\bf v}}_{\text{Diffusion}} - \underbrace{\nabla \Phi}_{\text{Gravity}} + \underbrace{{\bf F}}_{\begin{smallmatrix} \text{External} \\ \text{Forces} \end{smallmatrix}}</math>where <math>p</math> is the [[pressure]], <math>\nu</math> is the [[kinematic viscosity]], <math>\Delta</math> is the [[Laplace operator]], and <math>\Phi = gz</math> is the [[gravitational potential]]. By invoking the high Reynolds number and 1D flow assumptions, we have the equations:<math display="block">\begin{aligned}
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h &= e + {p\over{\rho g}} \\
&= {u^{2}\over{2g}} + z + {p\over{\gamma}}
\end{aligned}</math>with <math>\gamma = \rho g</math> being the [[specific weight]]. However, realistic systems require the addition of a [[head loss]] term <math>h_{f}</math> to account for energy [[dissipation]] due to [[friction]] and [[turbulence]] that was ignored by discounting the external forces term in the momentum equation.
==See also==
{{colbegin|colwidth=22em}}
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**[[Hydraulic jump]]
**[[Manning formula]]
**[[
**[[Standard step method]]
{{colend}}
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*[https://www.youtube.com/watch?v=7tjf8HWiR3Y What is a Hydraulic Jump?]
*[https://www.youtube.com/watch?v=RXWknY6zaY4 Open Channel Flow Example]
*[https://web.stanford.edu/class/me469b/handouts/turbulence.pdf Simulation of Turbulent Flows] (p.
{{Hydraulics}}
[[Category:Civil engineering]]
[[Category:Fluid dynamics]]
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