Content deleted Content added
m cleaned some math formatting |
m →Encoding: more direct links |
||
Line 49:
In other words, the entangled state shared between Alice and Bob has not changed, i.e. it is still <math>|\Phi ^{+}\rangle</math>. The notation <math>|B_{00}\rangle</math> is also used to remind us of the fact that Alice wants to send the two-bit string 00.
2. If Alice wants to send the classical two-bit string 01 to Bob, then she applies the [[Quantum logic gate#X|quantum ''NOT'' (or ''bit-flip'') gate]], <math>X = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} </math>, to her qubit, so that the resultant entangled quantum state becomes
:<math>|B_{01}\rangle = \frac{1}{\sqrt{2}}(|1_A0_B\rangle + |0_A1_B\rangle)</math>
3. If Alice wants to send the classical two-bit string 10 to Bob, then she applies the [[Quantum logic gate#Phase shift gates|quantum ''phase-flip'' gate]] <math>Z = \begin{bmatrix} 1 & 0 \\ 0 & -1 \end{bmatrix}</math> to her qubit, so the resultant entangled state becomes
:<math>|B_{10}\rangle = \frac{1}{\sqrt{2}}(|0_A0_B\rangle - |1_A1_B\rangle)</math>
| |||