Two-way finite automaton: Difference between revisions

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Small clarification
Line 39:
:<math>\delta(q,L)=(q^\prime,\mathrm{right})</math> for some <math>q^\prime \in Q</math>
:<math>\delta(q,R)=(q^\prime,\mathrm{left})</math> for some <math>q^\prime \in Q</math>
It says that there must be some transition possible when the pointer onreaches theeither alphabetend reachesof the endinput word.
* For all symbols <math>\sigma \in \Sigma \cup \{L\}</math>
: <math>\delta(t,\sigma)=(t,R)</math>