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{{AfC submission|t||ts=20211129025414|u=Unubold Lake Munkhbat Choros|ns=118|demo=}}<!-- Important, do not remove this line before article has been created. -->
Common graphs are closely related to other graph notions dealing with homomorphism density inequalities. For example, common graphs are a more general case of Sidorenko graphs (graphs with [[Sidorenko's conjecture#Statement|Sidorenko's property]])
== Definition ==
Formally,
<math>t(F, W) + t(F, 1 - W) \ge 2^{-e(F)+1}</math>
In other words, if we think of edges and non-edges as [[Edge coloring|2-coloring of edges]] of complete graph on the same vertices, then at least <math>2^{-e(F)}</math> fraction of all possible copies of <math>F</math> are monochromatic. The above definition using the generalized homomorphism density can be understood in this way. == Examples ==
* As stated above, all Sidorenko graphs
* The [[triangle graph]] <math>K_{3}</math> is
*
* Non-example: It was believed for a time that all graphs are common
== Proofs ==
In this section, we will prove some of the above examples.
Recall that a Sidorenko graph <math>F</math> is a graph satisfying <math>t(F, W) \ge t(K_2, W)^{e(F)}</math> for all graphons <math>W</math>. Hence, we should also have <math>t(F, 1 - W) \ge t(K_2, 1 - W)^{e(F)}</math>. Now, observe that <math>t(K_2, W) + t(K_2, 1 - W) = 1 </math>, which follows from the definition of homomorphism density. Combining this with [[Jensen's inequality]] for the function <math>f(x) = x^{e(F)}</math>, we can see that
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Thus, the conditions for common graph is met.
Here, we will expand the integral expression for <math>t(K_3, 1 - W)</math> and take into account the symmetry between the variables
<math>\int_{[0, 1]^3} (1 - W(x, y))(1 - W(y, z))(1 - W(z, x)) dx dy dz
= 1 - 3 \int_{[0, 1]^2} W(x, y) + 3 \int_{[0, 1]^3} W(x, y) W(x, z) dx dy dz - \int_{[0, 1]^3} W(x, y) W(y, z) W(z, x) dx dy dz</math>
Now, observe that each term in the expression can be written in terms of homomorphism densities of smaller graphs. Indeed, by the definition of homomorphism densities, we have
:<math>\int_{[0, 1]^2} W(x, y) dx dy = t(K_2, W) </math> :<math>\int{[0, 1]^3} W(x, y) W(x, z) dx dy dz = t(K_{1, 2}, W) </math> :<math>\int_{[0, 1]^3} W(x, y) W(y, z) W(z, x) dx dy dz = t(K_3, W)</math> ( :<math>t(K_3, W) + t(K_3, 1 - W) = 1 - 3 t(K_2, W) + 3 t(K_{1, 2}, W) </math>. Now, in order to relate <math>t(K_{1, 2}, W)</math> to <math>t(K_2, W)</math>, note that we can exploit the symmetry between the variables <math>y </math> and <math>z</math> to write
<math display=block>\begin{alignat}{4}
t(K_{1, 2}, W) &= \int_{[0, 1]^3} W(x, y) W(x, z) dx dy dz && \\ &= \int_{x \in [0, 1]} \bigg( \int_{y \in [0, 1]} W(x, y) \bigg) \bigg( \int_{z \in [0, 1]} W(x, z) \bigg) && \\
&= \int_{x \in [0, 1]} \bigg( \int_{y \in [0, 1]} W(x, y) \bigg)^2 && \\
&\ge \bigg( \int_{x \in [0, 1]} \int_{y \in [0, 1]} W(x, y) \bigg)^2 = t(K_2, W)^2
\end{alignat}</math>
where we used the integral [[Cauchy–Schwarz inequality]] in the last step. Finally, our desired result follows from the above inequality
<math>t(K_3, W) + t(K_3, 1 - W) \ge 1 - 3 t(K_2, W) + 3 t(K_{2}, W)^2
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