Content deleted Content added
→C++ (since C++11): Already possible |
m →C++ (since C++11): Explicitly show that the lambda and the function pointer have the same type |
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Line 708:
<syntaxhighlight lang="cpp">
auto a_lambda_func = [](int x) -> void { /*...*/ };
void (* func_ptr)(int) = a_lambda_func;
func_ptr(4); //calls the lambda.
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