Cantor function: Difference between revisions

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m added small note about bounded variation
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#Express <math>x</math> in base 3.
#If the base-3 representation of <math>x</math> contains a 1, replace every digit strictly after the first 1 bywith 0.
#Replace any remaining 2s with 1s.
#Interpret the result as a binary number. The result is <math>c(x)</math>.