Bühlmann decompression algorithm: Difference between revisions

Revision as of 12:06, 15 April 2024

Revision as of 22:02, 16 May 2024

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<math>t_{1/2}(\text{tx }18/50)= \frac{(1.51 \times 0.5)+ (4 \times 0.32)}{0.50 + 0.32}=\frac{(0.755 + 1.28)}{0.82}=2.48 </math> (instead of <math>1.51</math> with <math>He</math> and <math>4</math> with <math>N_2</math>)

<math>a (\text{tx }18/50)= \frac{(1.74747424 \times 0.5)+ (1.2599 \times 0.32)}{0.50 + 0.32}=\frac{(0.8737 + 0.403)}{0.82}=1.55695541 </math> (<math>1.74747424</math> with <math>He</math> and <math>1.2599</math> with <math>N_2</math>)

<math>b (\text{tx }18/50)= \frac{(0.4245 \times 0.5)+ (0.5050 \times 0.32)}{0.50 + 0.32}=\frac{(0.2122 + 0.1616)}{0.82}=0.4559 </math> (<math>0.4245</math> with <math>He</math> and <math>0.5050</math> with <math>N_2</math>)