Time hierarchy theorem: Difference between revisions

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Equivalently, if <math>f, g</math> are time-constructable, and <math>f(n) \ln f(n) = o(g(n))</math>, then
 
<math display="block">\operatornamemathsf{DTIME}(f(n)) \subsetneq \operatornamemathsf{DTIME} (g(n))   </math></blockquote>
 
'''Note 1.''' ''f''(''n'') is at least ''n'', since smaller functions are never time-constructible.<br>