Talk:Deutsch–Jozsa algorithm: Difference between revisions

Revision as of 15:30, 8 July 2007

Revision as of 15:31, 8 July 2007

Line 29:

== sharlatans ==

I think, that people who gave formula how calculate Deutsch-Jzosa algorithm, himselfs don't understood what they do. Becouse imposible to calculate somehingsomething concrete with this selfinvent trough dreams formula <math>\frac{1}{2^n}\sum_{x=0}^{2^n-1} (-1)^{f(x)} \sum_{y=0}^{2^n-1}(-1)^{x\cdot y} |y\rangle=

\sum_{y=0}^{2^n-1} [\sum_{x=0}^{2^n-1}(-1)^{f(x)} (-1)^{x\cdot y}] |y\rangle </math>.