Indeterminate form: Difference between revisions

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:<math>\lim_{x\rightarrow 49}{x-49\over\sqrt{x}\,-7}=14.</math>
 
Direct substitution of the limit into either of these functions leads to the indeterminate form 0/0, but both limits actually exist and are 1 and 14 respectively.
In the first case, "0/0" becomes 1; in the second case, "0/0" becomes 14.
 
The indeterminate form does not imply the limit does not exist. [[Algebraic elimination]] or applying [[L'Hopital's rule]] can be used to simplify the expression so the limit can be more easily and actually evaluated.