Cantor–Zassenhaus algorithm: Difference between revisions

Content deleted Content added
Background: \align
Line 17:
g(x) & {} \equiv g_2(x) \pmod{p_2(x)}, \\
& {} \vdots \\
& g(x) & {} \equiv g_s(x) \pmod{p_s(x)},
\end{align}
</math>