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The set V<sup>*</sup> is larger than it absolutely needs to be. It turns out that it suffices to use functionals of the form
:<math>
\phi_v\left(f\right)=\int_0^1\int_0^1 v\left(x,y\right) f\left(x,y\right) dxdy,
</math>
where ''v'' satifies the specified (periodic) boundary conditions.
That is, we are now replacing the original problem with that of finding ''u'' in V so that
:<math>
\phi_v\left(\mathrm{L}u\right)=\phi_v\left(g\right)
</math>
:φ<sub>''v''</sub>(L''u'')=φ<sub>''v''</sub>(''g'')
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