Integration using Euler's formula: Difference between revisions

Revision as of 18:24, 31 August 2008

Revision as of 11:51, 6 November 2008

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<math>\mathrm{Re}\{ \int e^{(i+1)x} dx \}</math>

This calculation continues as:

=Re (1/(1+i)) * exp((1+i)*x)

=Re ( 1/2 + i*1/2 ) * exp(x) * (cos (x) +i*sin(x))

=Re 1/2*exp(x)*cos(x)+1/2*i*exp(x)*sin(x)-1/2*i*exp(x)*cos(x)+1/2*exp(x)*sin(x)

=1/2 exp(x)*cos(x) + 1/2 exp(x)*sin(x)

[[Category:Integral calculus]]