Integration using Euler's formula: Difference between revisions

Revision as of 00:53, 1 July 2009

Revision as of 03:42, 16 November 2009

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At this point we can either integrate directly, or we can first change the integrand to cos 6''x'' + 2 cos 4''x'' + cos 2''x'' and continue from there.

Either method gives

:<math>\int \sin^2 x \cos 4x \, dx \,=\, -\frac{1}{4824}\sin 6x - \frac{1}{168}\sin 4x - \frac{1}{168}\sin 2x + C.</math>

==Using real parts==