Talk:Deutsch–Jozsa algorithm: Difference between revisions

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DavidBoden (talk | contribs)
DavidBoden (talk | contribs)
Line 53:
 
The starting point is:
<math>{\color{Blue}\frac{1}{\sqrt{2}}(|0\rangle + |1\rangle)}\frac{1}{\sqrt{2}}(|0\rangle - |1\rangle)</math> which can also be represented as the vector <math>\frac{1}{2}\bigl( \begin{smallmatrix}1\\ -1 \\ 1 \\ -1 \end{smallmatrix} \bigr)</math>
 
Applying <math>f(x)</math> gives