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: Yes, reg3 does not affect output 1 in direct way - by the argument you describe. However, reg3 affect reg1 : reg1=input+(reg2+reg3), and hence affect output 1 on the next performance cycle. [[User:Alexander Chervov|Alexander Chervov]] ([[User talk:Alexander Chervov|talk]]) 18:42, 8 October 2009 (UTC)
▲: I wonder if the author intended the adder above/between reg1/reg2 to add the encoder input to the reg1 output; this is based on the numerator of the first transfer function. Check my work:
* <math>reg_1=(1+reg_2+reg_3)*z^{-1},\,</math>
* <math>reg_2=reg_1*z^{-1},\,</math>
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now, I see the first transfer function from the drawing as:
: <math>H_1=input+reg_2+reg_3+reg_1+reg_3=input+reg_1+reg_2=\frac{1+z^{-1}+z^{-2}}{1-z^{-2}-z^{-3}},\,</math>
[[Special:Contributions/64.203.138.235|64.203.138.235]] ([[User talk:64.203.138.235|talk]]) 19:41, 30 November 2009 (UTC)▼
With the change I supposed above, the transfer function would be:
: <math>H_1=input+reg_1+reg_3=\frac{1+z^{-1}+z^{-3}}{1-z^{-2}-z^{-3}},\,</math>
: This matches the author's stated transfer function
▲[[Special:Contributions/64.203.138.235|64.203.138.235]] ([[User talk:64.203.138.235|talk]]) 19:
== Turbo Code for Planetary Exploration? ==
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