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'''Simonton Lake''' is a [[census-designated place]] located in [[Elkhart County, Indiana]].
==Geography==
Simonton Lake is located at 41
According to the [[United States Census Bureau]], the CDP has a total area of 9.5 [[square kilometer|km²]] (3.7 [[square mile|mi²]]).
==Demographics==
As of the [[census]]{{GR|2}} of 2000, there were 4,053 people, 1,567 households, and 1,181 families residing in the CDP.
There were 1,567 households out of which 31.8% had children under the age of 18 living with them, 64.2% were [[Marriage|married couples]] living together, 7.4% had a female householder with no husband present, and 24.6% were non-families. 19.5% of all households were made up of individuals and 6.6% had someone living alone who was 65 years of age or older.
In the CDP the population was spread out with 24.6% under the age of 18, 6.4% from 18 to 24, 28.4% from 25 to 44, 28.7% from 45 to 64, and 11.9% who were 65 years of age or older.
The median income for a household in the CDP was $56,539, and the median income for a family was $58,359. Males had a median income of $41,688 versus $26,901 for females. The [[per capita income]] for the CDP was $27,327.
==External links==
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