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Since <math> x_{k+1} = y_{k+1} </math> and assuming <math> x_0 = y_0 </math>, then <math>x_j=y_j</math> for all <math> j \ge 0</math>, and hence we can simplify the iteration to <math> x_{k+1} = \frac{1}{2}( \mathcal{P}_C(x_k) + \mathcal{P}_D(x_k) ) </math>.
== YOUR MOMMA
== References ==
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