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Line 25:
* b, I<sub>p→x</sub>≥ I<sub>p</sub> + t (brighter)
Then choosing an x
* P<sub>d</sub> = {p ∈ P : S<sub>p→x</sub> = d }
* P<sub>s</sub> = {p ∈ P : S<sub>p→x</sub> = s }
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Line 25:
* b, I<sub>p→x</sub>≥ I<sub>p</sub> + t (brighter)
Then choosing an x
* P<sub>d</sub> = {p ∈ P : S<sub>p→x</sub> = d }
* P<sub>s</sub> = {p ∈ P : S<sub>p→x</sub> = s }
|