Multiplication algorithm: Difference between revisions

Revision as of 03:49, 8 February 2014

Revision as of 01:35, 10 February 2014

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The method works because multiplication is [[distributivity|distributive]], so:

:3×11= 3×(1×2⁰ + 1×2¹ + 0×2² + 1×2³)

: <math>

:: = 3×(1 + 2 + 8)

\begin{align}

:: = 3 + 6 + 24

3 \times 11 & = 3 \times (1\times 2^0 + 1\times 2^1 + 0\times 2^2 + 1\times 2^3) \\

:: = 33.

::& = 3×3 \times (1 + 2 + 8) \\

::& = 3 + 6 + 24 \\

::& = 33.

\end{align}

</math>

A more complicated example, using the figures from the earlier examples (23,958,233 and 5,830):