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In the code fragment below, the expression (x + y) is loop invariant, and the addition can be hoisted out of the loop.
<source lang="C">
void f (int x, int y)
{
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}
}
</
Below is the code fragment after the invariant expression has been hoisted out of the loop.
<source lang="C">
void f (int x, int y)
{
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}
}
</
Notes:
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