Extouch triangle: Difference between revisions

Revision as of 15:56, 4 February 2016

Revision as of 02:14, 23 July 2016

Line 9:

:<math>T_C = \csc^2{\left( A/2 \right)} : \csc^2{\left( B/2 \right)} : 0</math>

Or,or equivalently, where a,b,c are the lengths of the sides opposite angles A, B, C respectively,

:<math>T_A = 0 : \frac{a-b+c}{b} : \frac{a+b-c}{c}</math>

:<math>T_B = \frac{-a+b+c}{a} : 0 : \frac{a+b-c}{c}</math>

:<math>T_C = \frac{-a+b+c}{a} : \frac{a-b+c}{b} : 0.</math>

==Related figures==