Bartels–Stewart algorithm: Difference between revisions

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=== Simplifications and special cases ===
 
In the special case where <math>B=-A^T</math> and <math>C</math> is symmetric, the solution <math>X</math> will also be symmetric. This symmetry can be exploited so that <math>Y</math> is found more efficiently in step 3 of the algorithm<ref name=":0" />.
 
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{{Numerical linear algebra}}
 
[[Category:Algorithms]]
[[Category:Control theory]]
[[Category:Matrices]]
[[Category:Numerical linear algebra]]
 
{{improve categories|date=November 2018}}