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Thatsme314 (talk | contribs) |
Alsosaid1987 (talk | contribs) fix english to be more idiomatic |
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:<math>\left(\bigcap_{k} C_k\right) \neq \emptyset. </math>
''Note'': We may
=== Proof ===
Assume, by way of contradiction, that <math>\bigcap C_n=\emptyset</math>. For each n, let <math>U_n=C_0\setminus C_n</math>. Since <math>\bigcup U_n=C_0\setminus\bigcap C_n</math> and <math>\bigcap C_n=\emptyset</math>, we have <math>\bigcup U_n=C_0</math>.
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