Revision as of 16:24, 9 July 2019 edit Chetvorno (talk \| contribs) Extended confirmed users 66,715 edits Reverted good faith edits by Alej27: Inductors and capacitors are still linear components because differentiation and integration are linear operations, so the relation of current and voltage in these components is still linear: doubling the amplitude of a voltage waveform applied to a capacitor doubles the current in the capacitor (TW) Tag: Undo ← Previous edit		Revision as of 16:54, 9 July 2019 edit undo Chetvorno (talk \| contribs) Extended confirmed users 66,715 edits Reverted 1 edit by Chetvorno (talk): Sorry, User:Alej27, you were right, that is an error (TW) Tag: Undo Next edit →
Line 4: == Overview == Many of the [[electrical component]]s used in simple electric circuits, such as [[resistor]]s, [[inductor]]s, and [[capacitor]]s are [[linear circuit\|linear~~]], which means the [[electric current\|current]] in them is proportional to the applied [[voltage~~]]. Circuits made with these components, called [[linear circuit]]s, are governed by [[linear differential equation]]s, and can be solved easily with powerful mathematical methods such as the [[Laplace transform]]. In contrast, many of the components that make up ''electronic'' circuits, such as [[diode]]s, [[transistor]]s, [[integrated circuit]]s, and [[vacuum tube]]s are [[linear circuit\|nonlinear]]; that is the current through them is not proportional to the voltage, and the output of [[two-port network\|two-port]] devices like transistors is not proportional to their input. The relationship between current and voltage in them is given by a curved line on a graph, their [[Current-voltage characteristic\|characteristic curve]] (I-V curve). In general these circuits don't have simple mathematical solutions. To calculate the current and voltage in them generally requires either [[graphical method]]s or simulation on computers using [[electronic circuit simulation]] programs like [[SPICE]].

Small-signal model: Difference between revisions