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→General: \Gamma(1/2-n) formula: the last equality is obvious wrong because \Gamma(-1/2)= -2\sqrt(\pi). Deleted from right = \frac{\sqrt{\pi}}{{-\frac12 \choose n} n!} |
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Line 231:
:<math>\begin{align}
\Gamma\left(\tfrac12+n\right) &= {(2n)! \over 4^n n!} \sqrt{\pi} = \frac{(2n-1)!!}{2^n} \sqrt{\pi} = \binom{n-\
\Gamma\left(\tfrac12-n\right) &= {(-4)^n n! \over (2n)!} \sqrt{\pi} = \frac{(-2)^n}{(2n-1)!!} \sqrt{\pi}
\end{align}</math>
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