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→Hadamard factorization theorem: explain square bracket, from entire function Tags: Mobile edit Mobile web edit Advanced mobile edit |
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The theorem, which is named for [[Karl Weierstrass]], is closely related to a second result that every sequence tending to infinity has an associated entire function with zeroes at precisely the points of that sequence.
A generalization of the theorem extends it to [[meromorphic function]]s and allows one to consider a given meromorphic function as a product of three factors: terms depending on the function's [[zeros and poles]], and an associated non-zero [[holomorphic function]].{{
==Motivation==
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The ''elementary factors''
,<ref name="rudin">{{citation|last=Rudin|first=W.|title=Real and Complex Analysis|edition=3rd|publisher=McGraw Hill|___location=Boston|pages=301–304|year=1987|isbn=0-07-054234-1|oclc=13093736}}</ref>
also referred to as ''primary factors''
,<ref name="boas">{{citation|last=Boas|first=R. P.|title=Entire Functions|publisher=Academic Press Inc.|___location=New York|year=1954|isbn=0-8218-4505-5|oclc=6487790}}, chapter 2.</ref>
are functions that combine the properties of zero slope and zero value (see graphic):
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while the [[gamma function]] <math>\Gamma</math> has factorization
<math display=block>\frac{1}{\Gamma (z)}=e^{\gamma z}z\prod_{n=1}^{\infty }\left ( 1+\frac{z}{n} \right )e^{-z/n},</math>
<math>\gamma</math> is the [[Euler–Mascheroni constant]].{{
<math display=block>\frac{1}{\Gamma(s-z)\Gamma(s+z)} = \frac{1}{\Gamma(s)^2}\prod_{n=0}^\infty \left( 1 - \left(\frac{z}{n+s} \right)^2 \right) </math>
for <math>s=\tfrac{1}{2}</math>.{{
===Hadamard factorization theorem===
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