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SirMeowMeow (talk | contribs) m Undid revision 1005809334 by Hellacioussatyr (talk) |
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Under the assumption that the feasible region is non-empty and bounded, the Charnes-Cooper transformation<ref name="CC"/>
:<math>\mathbf{y} = \frac{1}{\mathbf{d}^
translates the linear-fractional program above to the equivalent linear program:
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:<math>
\begin{align}
\text{maximize} \quad & \mathbf{c}^
\text{subject to} \quad & A\mathbf{y} \leq \mathbf{b} t \\
& \mathbf{d}^
& t \geq 0.
\end{align}
</math>
Then the solution for <math>\mathbf{
:<math>\mathbf{x}=\frac{1}{t}\mathbf{y}.</math>
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