Talk:Euler's totient function/Archive 1: Difference between revisions

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m Archiving 1 discussion(s) from Talk:Euler's totient function) (bot
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:::::In Wikipedia, decisions are taken by consensus, as described in details in [[WP:CON]]. However, few people have given their opinion. One could start a [[WP:request for comments]]. But, as nobody disagrees formally with you, and your arguments are convincing, I have self-reverted my revert of your edits. The change of title (called [[WP:moving a page|move]] in WP) seems less important than editing the content, because the title you suggest exists as a [[WP:redirect]]. For technical reasons, it may be done (in this case) only through a [[WP:move request]]. [[User:D.Lazard|D.Lazard]] ([[User talk:D.Lazard|talk]]) 19:12, 15 April 2015 (UTC)
 
== Totient numbers ==
This section contains {{tq|there are infinitely many nontotients, and indeed every odd number has an even multiple which is a nontotient}}, the word "even" being added by a recent edit. In both versions, this sentence is a nonsense, as every odd number greater than 1 is a nontotient; thus no need to consider multiples. I guess that the correct assertion should be {{tq|every totient has a multiple (by an odd number) that is a nontotient}}. However this needs to be checked on the source. [[User:D.Lazard|D.Lazard]] ([[User talk:D.Lazard|talk]]) 09:59, 25 April 2015 (UTC)
: As you say, odd numbers greater than 1 are trivially nontotients, so what is of interest is the existence of even nontotients. I imagine the previous writer meant "there are infinitely many even nontotients, and indeed..." but just forgot the "even". I've checked the paper and in fact it proves that any number (even or odd) has a multiple which is a nontotient. If n is odd then the nontotient multiple of 2n gives an even nontotient multiple of n, so this is equivalent to saying any number has an even nontotient multiple. I'll make those changes. [[User:Especially Lime|Especially Lime]] ([[User talk:Especially Lime|talk]]) 08:54, 20 May 2016 (UTC)