Modular lambda function: Difference between revisions

Revision as of 10:22, 6 May 2021

Revision as of 10:26, 12 May 2021

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:<math>\lambda^*(10) = (\sqrt{10}-3)(\sqrt{2}-1)^2</math>

:<math>\lambda^*(14) = \tan\{\frac{1}{2}\arctan[\frac{1}{648}(2\sqrt{2}+1-\sqrt{24\sqrt{2}-1+5})^63]\}</math>

:<math>\lambda^*(18) = (\sqrt{2}-1)^3(2-\sqrt{3})^2</math>

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:<math>\lambda^*(30) = \tan\{\frac{1}{2}\arctan[(\sqrt{10}-3)^2(\sqrt{5}-2)^2]\}</math>

:<math>\lambda^*(34) = \tan\{\frac{1}{24}\arctanarcsin[\frac{1}{649}(\sqrt{17}+-4)^3(15-3\sqrt{17}-\sqrt{38\sqrt{17}-150})^32]\}</math>

:<math>\lambda^*(42) = \tan\{\frac{1}{2}\arctan[(2\sqrt{7}-3\sqrt{3})^2(2\sqrt{2}-\sqrt{7})^2]\}</math>

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:<math>\lambda^*(58) = (13\sqrt{58}-99)(\sqrt{2}-1)^6</math>

:<math>\lambda^*(62) = \tan\{\frac{1}{2}\arctan[\frac{1}{512}(\sqrt{\sqrt{380\sqrt{2}+529}+10\sqrt{2}+19}-\sqrt{\sqrt{380\sqrt{2}+529}+10\sqrt{2}+11})^6]\}</math>

:<math>\lambda^*(70) = \tan\{\frac{1}{2}\arctan[(\sqrt{5}-2)^4(\sqrt{2}-1)^6]\}</math>