Talk:Jordan matrix: Difference between revisions

Revision as of 05:19, 20 July 2009

Revision as of 00:47, 25 July 2021

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The section on ODE's doesn't mention one of the more basic characteristics of Jordan blocks, which is that a block of size k gives rise to a solution term of the form <math>t^{k-1}e^{at}</math> or something like that. These powers of t don't occur in the "usual" case where the matrix is diagonalizeable. Maybe I'll see if I can update the article. [[Special:Contributions/67.117.147.249|67.117.147.249]] ([[User talk:67.117.147.249|talk]]) 02:23, 20 July 2009 (UTC)

== Functions of matrices ==

{{ping|Anita5192}} the <math>f(J_{\lambda, n})</math> matrix should be a function of <math>\lambda</math>. The form you reverted back to the article is only true for <math>\lambda=0</math>. For example, for <math>\lambda=1</math> and <math>f(A)=A</math> the diagonal would be equal to <math>\lambda</math>, not <math>a_0=0</math>. If you want to keep it as it is, the <math>\lambda=0</math> property should be specified somewhere. <span style="font:111% Helvetica Neue;font-weight:bold;">adamant.pwn</span> — <small>[[Special:Contributions/adamant.pwn|contrib]]/[[User talk:adamant.pwn|talk]]</small> 00:47, 25 July 2021 (UTC)